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Wednesday, 1 June 2016

My first time scuba diving

My diving trip to perhentian Island 

I have never dived before and the closest I've been in the water is swimming on the surface or snorkel. For first timers or those who are about to do it, go for it! It's an opportunity no one should ever miss. The beauty is enthralling and as a person who never really took care about the environment, I'm now one of those people who tries to be eco-friendly at all time.  
My schedule was as shown below.


Thursday (18/6)
Depart from office in KL at 11pm taking the bus ( my company's trip)

Friday (19/6)
Reached kuala besut jetty at 7am
Took boat to island, checked in the chalet at 10.30am
Started diving lessons at 11am.
Was briefed on the basics of diving and how to assemble the equipments properly. Got measured for my fins and wet suit. I strongly recommend that whoever is doing first dive to get a rash guard of their own (preferably long sleeve) and if you got your own mask and snorkel piece, that's fine too. If it's new, just use a lighter to burn the edges of the rubber mask slightly to ensure its comfortable to wear.

First dive : 12pm (1.5hrs-est.) - learned the basic swimming techniques and signals for divers such as OK, up, down, oxygen is at baseline and etc. We were at an enclosed water at a nearby beach with depth up to 10m deep.
Debrief
Lunch break - try not to eat anything heavy. Replenish on water or isotonic drink is fine. Sandwiches would do.

Second dive : 4pm (3 hrs)
Debrief
Dinner

Saturday (20/6)
Breakfast 
Diving lesson
First dive : 8.30am (1.5 hrs)
Debrief 
Lunch
Second dive : 1.30pm (1 hr)
Debrief
Free n easy
Quiz and exam - use common sense please. Don't try to murder your partner accidentally and don't do stunts in the water.

Sunday (21/6)
Breakfast
Diving lesson : 8.15 am
First dive: 8.30am ( 1hr)
Debrief
Lunch
Second dive: 11.30am ( 51 mins)
Debrief 
Third dive: 1.30pm (53 mins)
Debrief
Certified open water diver
Shower: 3pm

Head back to k.besut jetty at 4pm
Left jetty at 4.30pm
Reached office at 12.40am

Due to the super packed agenda, I was able to complete my dive within 3 days and 2 nights trip.

I had other dives after that :)

Hope you enjoy your first experience.

Monday, 30 May 2016

Synthesis & Characterization of a Metal Hydride Complex

*disclaimer* please use it only as reference and not copy the work word for word...

Title: Synthesis & Characterization of a Metal Hydride Complex

Objective
1.     To synthesis a cobalt hydride complex and deduce its chemical structure based on the spectral data.

Introduction
            Hydrogen atom, H can coordinate to the transition metal center as σ-donor ligand or as σ-ligand. When it acts as a σ-ligand, it coordinates to the metal center through the single bond between the two hydrogen atoms, H-H and results in a dihydrogen complex. However, it can also coordinate to the transition metal center through hydride form, H- and produce dihydride complex, and are commonly known as covalent hydrides. The following figure shows the difference between the dihydrogen and dihydride complex.

                                                              (no image available)
(I)                                            (II)
Figure 1 Structure (I) and (II) represents a general structure for dihydrogen and dihydride metal complex respectively

            Metal hydride complexes are important as intermediates in many catalytic processes such as alkene oligomerization and hydrogenation. Recently, there also have been a lot of researches on metal hydride complex as a potential candidate for fuel storage for energy consumption applications and as prospective materials for neutron radiation shielding (Stepien, 2005). However, it requires techniques of compressing gaseous hydrogen to pressure of a few gigapascals to synthesize hydrides of most transition metals, such as cobalt hydrides. In order to synthesize metal hydride complexes, a number of preparation methods can be used included (i) protonation (requires an electron rich basic metal center), (ii) from hydride donors (main group metal hydrides), (iii) from H2 (via oxidative addition – requires a coordinatively unsaturated metal center),  and (iv) from a ligand (β-elimination).
A metal hydride may have acidic or basic character depending on the electronic nature of the metal involved and its ligand set. Early transition metal hydrides tend to carry significant negative charge on the H atom whereas later more electronegative transition metals favour a more positive charge on the H atom, thus the term hydride should not be taken literally. In this experiment, we are going to synthesize organophosphine derivative of cobalt hydride complexes from a hydride donor, sodium borohydride (NaBH4) in the presence of excess ligands. Sodium borohydride is an ionic hydride which liberates hydrogen gas immediately after dissolve in water. It is also a good reducing agent that finds wide application in laboratory and on a technical scale, especially in bleaching the wood pulp. It is used in this experiment to reduce the oxidation state of the cobalt metal center and to provide source of hydride ions as ligand. On the other hand, cobalt hydride complex with the triphenylphosphite is the first examples of metal hydrides stabilized by phosphite ligands. Triphenylphosphite is a bulky ligand when coordinate to the metal center through the lone pair electrons on the P-atom. This bulky ligand will exert steric effect on the metal complexes and thus blocks the larger size ligand from coordinate to the cobalt metal center. Obviously, the smaller size of hydride has no problem to coordinate to the cobalt metal center. However, coordinated hydride ligand often cause distorted geometry in this cobalt complex.

Procedures
Part A: Preparation of Metal Hydride
1.     A solution of 0.5 g of sodium borohydride in 10 mL is added dropwise to a stirred solution of cobalt(II) nitrate hydrate (1.5 g) and triphenylphosphite (8.0 g) in 30 mL ethanol at 25 °C.
2.     After 15 minutes, the solid is filtered, washed with ethanol, water and finally methanol and dried at the pump.
3.     The product was recrystallized by dissolving in 30 mL of dichloromethane and filtered to obtain a clear dichloromethane solution.

Part B: Characterization of Product
1.     The yield of the product was recorded.
2.     IR and 1H NMR spectrum of the complex was obtained.
Results & Calculations
Table 1 Weight of materials used and products formed.
Materials
Weight (g)
NaBH4
0.5781 g
Co(NO3)2 • 6 H2O
1.5873g
P(OPh)3
8.0773 g
Beaker
105.7246g
Beaker + Product
107.4530g
Product
1.4284g

Co2+ + 4 P(OPh)3 + H- + e-                 HCo[P(OPh)3]4

Moles of Co2+ = Moles of Co(NO3)2 • 6 H2O used
                        = 1.5873 g / 291.0352 g mol-1
                        = 5.45 x 10-3 mol

Moles of H- = Moles of NaBH4 used × 4
                    = (0.5781 g / 37.83 g mol-1) × 4
                    = 6.11 x 10-2 mol

Moles of P(OPh)3 used = 8.0773 g / 310.28 g mol-1
                                      = 2.60 x 10-2 mol

If P(OPh)3 is the limiting reagent, then:
Moles of HCo[P(OPh)3]4 produced = Moles of P(OPh)3 / 4
         = 2.60 x 10-2 mol / 4
         = 6.51 x 10-3  mol
.
From the calculation above, it shows that Co(NO3)2 • 6 H2O is the limiting reagent.
Therefore, moles of HCo[P(OPh)3]4 produced = Moles of Co2+
                                                                           = 5.45 x 10-3 mol
Theoretical weight of HCo[P(OPh)3]4 produced = 5.45 x 10-3 mol × 1301.05 g mol-1
                                                                              = 7.091g

Percentage yield of HCo[P(OPh)3]4 = (1.4284 g / 7.091 g) × 100 %
                                                          = 20.14 %

Table 2 IR frequencies of starting material and products formed.
Compound 1: Cobalt (II) nitrate hydrate
Significant signals
Expected (from table)
Wavenumber (cm-1)
Observed (from spectrum)
O-H stretch
3200-3550
3403
Asymmetric NO2 stretch
1450-1600
1629
Symmetric NO2 stretch
1260-1375
1384


Compound 2: Triphenylphosphite
Significant signals
Expected (from table)
Wavenumber (cm-1)
Observed (from spectrum)
Aromatic C=C stretch
1400-1600
1481, 1590
=C-H stretch
3010-3100
3062, 3038
C-P stretch
700
746


Compound 3: Hydirotetrakis(triphenylphosphito)cobalt (II)
Significant signals
Expected (from table)
Wavenumber (cm-1)
Observed (from spectrum)
=C-H stretch
3010-3100
3067
Aromatic C=C stretch
1400-1600
1490, 1591
Co-H stretch
1745-1933
absent
C-P stretch
700
691





Table 3 1H NMR spectrum of complex
Chemical shift (ppm)
~ − 11.5
~ 7.5
Division
11mm / 10 = 1.1 mm
66 mm
Ratio
1.1 / 1.1 = 1
66 / 1.1 = 60
Integration
1
60
Types of Proton
−H
12 × −C6H5

Discussion
From the experiment above, the percentage yield of product is calculated to be 20.14 % . Sodium borohydride (NaBH4) was used for it is a good reducing agent and provides the hydride ions, H-  and electrons to the complex, which reduces Co2+ to Co+. From the IR spectrum of Co(NO3)2 • 6 H2O, the peaks found were namely;
i)                O-H stretching frequency at 3403 cm-1
ii)              bending frequency of O-H at 1629 cm-1
iii)             Asymmetric stretching frequency of NO2 at 1384 cm-1.

As for hexahydrate nitrate ions, the IR frequencies included δ (O-H) at around 1575-1675 cm-1, as(NO2) between 1260-1375 cm-1 and 1450-1600 cm-1. On the other hand, IR spectrum of P(OPh)3 consist of sp2 C-H stretch frequency at 3062 cm-1 and 3038 cm-1, aromatic C=C stretch (1590 cm-1, 1481 cm-1), and P-C stretch (746 cm-1).

When comparing the IR spectrum, there were correlation between that starting material and the final product. It consisted of sp2 C-H stretch (3067 cm-1), aromatic C=C stretch (1591 cm-1, 1490 cm-1) and P-C stretch (757 cm-1). Absence of asymmetric stretching frequency of NO2 in the IR spectrum indicates that the complex formed does not contain any of the nitrate ions. Besides, there is also no O-H stretch frequency in the IR spectrum of the complex, indicating the complex if free from water molecules. Interestingly, no ν(M-H) can be detected in the infrared spectra of the cobalt complex that we have synthesized, but the presence of hydride ligands is confirmed by the appearance of a quintet pattern in the high-field NMR spectra (Levison & Robinson, 1972).

From the 1H NMR spectrum, there are only two types of proton present, which are –H at around −11.5 ppm and −C6H5 at around 7.5 ppm. Since there is only one –H, this could be attributed to the only one hydride ligand present in the complex synthesized. On the other hand, there is twelve −C6H5 functional group present in the complex, resulting in P(OPh)3 groups in the complex. Since there is no other ligands attached to the Co metal center after comparing both IR and 1H NMR spectrum, the chemical structure of the complex synthesized can be deduced as HCo[P(OPh)3]4. In this complex, the formal oxidation state for Co metal center is Co(I), which was reduced from Co(II). As there is only one anionic ligand attached to the Co metal center, with H- as a single negative charge and P(OPh)3 is a neutral ligand. Thus, the oxidation state of Co metal center in this neutral complex should be Co(I). Excess electrons that were used to reduce the oxidation state of Co(II) was obtained from the NaBH4. Below structure depicts the arrangement of the synthesized complex.

The P-atoms of the four triphenylphosphite ligands are disposed in a distorted tetrahedral geometry around the Co(I) ion. Hydride ligand is located at a location trans to one of the P-atoms, showing a monocapped tetrahedral complex with the hydride as the face-capping ligand. From the journal, (Crane & Young, 2004) has shown that the hydride ligand trans to one of the P-atoms was strongly indicated by the long Co-P bond distance of 2.1191 (7) Å caused by the trans influence of the hydride, and the pattern of bond angles subtended at the cobalt center. The location was confirmed by the high residual electron density observed at this position in the difference Fourier map and the subsequent successful free refinement of the positional parameters for the hydride ligand, with a Co-H distance of 1.36 (2) Å.

On the other hand, since cobalt is in Group 9, Co(I) has dn = d9-1 = d8, contributing 8 electrons towards electron counting. The anionic hydride ligand will contribute 2 electrons, and the four neutral P(OPh3) ligands will contribute 8 electrons, each contributes 2 electrons. Hence, the total electrons for the complex HCo[P(OPh)3]4 would be 8 + 2 + 8 =18 electrons.

Conclusion
The percentage yield of this complex is 20.14%. After comparing IR and 1H NMR spectrum, the cobalt hydride complex that have been synthesized is having the chemical formula of HCo[P(OPh)3]4. The geometry of this complex is monocapped tetrahedral and has an 18 electrons complex. The formal oxidation state of Co is Co (I).
References
1.     Daniel J. Goebbert, Etienne Garand, Torsten Wende, Risshu Bergmann, Gerard Meijer, Knut R. Asmis & Daniel M. Neumark (2009). Infrared Spectroscopy of the Microhydrated Nitrate Ions NO3- (H2O)1-6. J. Phys. Chem. A, 113, pp. 7584 – 7592.
2.     J. J. Levison & S. D. Robinson (1972). Inorganic Syntheses, Volume XIII. United States, U.S.: McGraw-Hill, Inc. Chapter 4, pp. 105 – 111.
3.     Jonathan D. Crane & Nigel Young (2004). Hydridotetrakis(triphenylphosphito)cobalt(I). Acta Crystallographica, E(60), m487 – m488.
4.     Zdzislaw M. Stepien (2005). Formation of Cobalt Hydrides in Low Temperature Field Evaporation. Optica Applicata, XXXV(3), pp. 363 – 368.

Tuesday, 20 November 2012

Title: Dehydration Of An Alcohol: Cyclohexene From Cyclohexanol

Title: Dehydration Of An Alcohol: Cyclohexene From Cyclohexanol Objective: To produce cyclohexene through the acid catalyzed elimination of water from cyclohexanol. To understand mechanism involved in the reaction. To learn the technique of distillation. Introduction: A secondary alcohol, such as cyclohexanol, undergoes dehydration by an E1 mechanism. The key intermediate in the mechanism is a cyclohexyl cation, which can undergo substitution as well as elimination. To prepare a cyclohexene (olefin) in good yield, it is necessary to suppress the substitution reaction. In this experiment, the substitution reaction is suppressed by: (1) the use of strong acids with anions that are relatively poor nucleophiles ; (2) a high reaction temperature, which favors elimination; and (3) distillation of cyclohexene from the reaction mixture as it is formed. The dehydration reaction is of paramount importance in the preparation of olefins, which are the raw materials of much of the plastics industry. From the historical point of view it is no less importance, because it has been used time and again in the laboratory in the preparation of important compounds. The first complete synthesis of the alkaloid morphine, for example, involved the use of an olefin intermediate, which was prepared by the dehydration methods. Side Reactions The side products of the dehydration reaction are virtually identical with those encountered in the preparation of n-amyl bromide, the only difference being that the olefin is no longer a side product but is now the desired product. Specifically, the side products are dicyclohexyl ether, polymer, mono and dicyclohexyl sulphate, and degradation products such as carbon, sulphur dioxide and carbon dioxide. The dehydration of cyclohexanol is carried out in such a way that the product, cyclohexene, distils from the reaction mixture as it is formed, the distillation technique serves to remove the olefin from contact with the sulphuric acid before polymerization can set in and it also serves as a first stage in the eventual purification of the olefin. The products and side products fall three categories: (a) gases, composed of sulphur dioxide and carbon dioxide and carbon dioxide, (b) distillate, composed of cyclohexene, un-reacted cyclohexanol, water and traces of sulphurous acid; and (c) residue, composed of high-boiling or non-volatile substances such as dicyclohexyl ether, mono- and dicyclohexyl sulphate, polymer and carbon. Pure cyclohexene is obtained from the crude distillate by the following procedure: Treatment with aqueous sodium carbonate solution to remove sulphurous acid; Addition of calcium chloride, to remove all of the water and part of the cyclohexanol; and Distillation to separate the remainder of the cyclohexanol. The dehydration of an alcohol with phosphoric acid instead of sulphuric acid has two distinct advantages: Very little organic material is lost through oxidation by the acid and The product is not contaminated with volatile decomposition products (e.g. sulphurous acid) Both advantages are attributable to the fact that phosphoric acid, unlike sulphuric acid is not an oxidizing agent. As a result, the yield of olefin is usually higher with phosphoric acid, the workup is simplified, and important from the point of view of the experimenter the labour required to clean the reaction flask is greatly reduced. (Sulphuric acid produces an intractable black tar which adheres tenaciously to the walls of the reaction flask.) Apparatus and Materials: Round-bottomed flask (50 mL), boiling chips, bunsen burner, take-off distillation adapter, condenser, thermometer, cyclohexanol, concentrated (85%) phosphoric acid, anhydrous magnesium sulphate. Experimental Procedure: 10.0 g of cyclohexanol and 2 mL of conc.(85%) phosphoric acid were placed in a 50 mL ST round bottomed flask and the two were mixed by swirling. Several carborundum porcelain or anthracite boiling chips (do not use marble chips) were added, the flask was clamped to a ring stand at Bunsen burner height, and a take-off distillation adapter was attached, a thermometer, a condenser, and a small receiving flask. The reaction mixture was heated so that it boils gently and distillate boiling in the range 85-90 ℃ was obtained. When the distillate was exhausted, the heat was increasing gradually. The same receiver was using; the distillate boiling was collected in the range of 90-100℃. The two liquid layers were tested in the receiving flask to see which the aqueous layer was. With the aid of a 9-in disposable pipette, the aqueous layer was drawn off and discarded the aqueous layer. The organic layer remaining in the receiving flask was dried by adding to it 0.1-0.2g of anhydrous magnesium sulphate. The resulting mixture was swirled for a minute or two, and then the drying agent was removed by filtering a mixture through a cotton wool plug wedged into the constricted part of a small funnel. The filtrate was collected in a 50-mL ST round-bottom flask or a small distilling flask. A boiling chip was added to the dried product and it was distilled through a take-off distillation adapter packed with a few small wads of coarse steel wool. The product boiling in the range 3 below to 2 above the boiling point of cyclohexene(83℃) was collected in a tarred bottle. Results and Calculations Weight of round-bottomed flask + beaker 86.15g Weight of round-bottomed flask + beaker + cyclohexene 96.05g Weight of cyclohexanol started with 9.90 g Weight of conical flask 43.93g Weight of conical flask + cyclohexene 46.38 g Weight of cyclohexene obtained 2.55 g Percent yield: 31.41% From the reaction, 1 mol of cyclohexanol produce 1 mol of cyclohexene. Molecular mass of cyclohexanol is 100 g mol-1. Mole of cyclohexanol = 9.90 g / 100 g mol-1 = 0.099mol Thus, 0.099 mol of cyclohexene was produced. Molecular mass of cyclohexene is 82 g mol-1. Mass of cyclohexene = 0.099 mol X 82 g mol-1 = 8.118g (Theoretical mass) Experimental mass = 2.55g Percentage of yield = experimental yield x 100 % Theoretical yield Percentage of yield = 2.55g x 100 % 8.118g Percentage of yield = 31.41% Question: Dehydration of cyclohexanol gives cyclohexene. Draw mechanism for the reaction. What alkene will be produced when each of the following alcohols is dehydrated? a) t-butyl alcohol CH3 CH3 CH3 – C –OH CH3 – C ═ CH2 + H2O CH3 2-methyl-1-propene b) 3-methylcyclohexanol 80% = 4-methylcyclohexene and 3-methylcyclohexene 20% = 1-methylcyclohexene The dehydration of 3,3-dimethyl-2-butanol yields three different products. Write equations to show how carbonation rearrangements explain two of the products. Elimination step 1 (Secondary carbocation): Product yield is (CH3)3CCH=CH2 (3,3 Dimethyl-1-butene). It is a normal elimination product and the least from the amount. Rearrangement of carbocation: Elimination step 2 (Tertiary carbocation): Product yield is 2,3-dimethyl-2-butene. It is the major product. Elimination step 3 (Tertiary carbocation): Product yield is 2,3-dimethyl-1-butene. It is the minor product. Discussion: Elimination reactions involve the loss of a small molecule (H-X) from adjacent carbon atoms, resulting in pi-bond formation. Consequently, elimination reactions are good synthetic methods for producing alkenes or alkynes. These reactions occur through a process called heterolytic bond cleavage. Heterolytic bond cleavage occurs when one atom leaves a compound with both electrons of the original bond, resulting in the formation of ions. For example, elimination of H-X from an organic molecule involves the loss of a proton (H+) and a leaving group (X-). The leaving group departs with both electrons from the original C-X bond. The electrons in the adjacent C-H bond form the new pi bond of the alkene, with the loss of the proton. The elimination of water (H-OH) from alcohols in this experiment is called a dehydration reaction. In many cases, alcohol dehydration is an acid-catalyzed reaction that proceeds by an elimination mechanism called E1. The key intermediate in the mechanism is a cyclohexyl cation, which can undergo substitution as well as elimination. To prepare an alkene in good yield, it is necessary to suppress the substitution reaction. In this experiment, the substitution reaction is suppressed by: (1) the use of strong acids with anions that are relatively poor nucleophiles; (2) a high reaction temperature, which favors elimination. The anion of phosphoric acids in this experiment is a poor nucleophile, and thus substitution reactions are not favored. The first step of dehydration is a proton transfer from the acid catalyst to the oxygen atom of the alcohol. This protonation forms a oxonium ion, the conjugate acid of the alcohol. Weak base are good leaving groups, so changing the leaving group from hydroxide to water favours the reaction. The second step of the dehydration reaction is loss of water from the oxonium ion forming a positively charged secondary carbocation. This step of the mechanism is rate determining. The ease of alcohol dehydration follows the trend 3° > 2° > 1°. The third and final step, a molecule of water deprotonates the carbocation at either of the adjacent carbons. The remaining electrons flow towards the positive charge producing a –bond between the carbons and forming a double bond. From the experiment, only 2.55g of cyclohexene was produced, which is 31.41 % from the theoretical mass. This is due to a significant amount of product left and lost during distillation. Since the connection of the distillation set has been closed fitly, thus it can be sure that some products were left in the flask and in the column. Hence, for recovery of otherwise lost reaction product, a “chaser” solvent e.g. toluene, should be added after the distillation and carry on distillation for second time. Once the toluene distils up the column and reaches the thermometer, most of the cyclohexene and water has been pushed over into the collection vial and maximum yield is ready to be collected. The anhydrous MgSO4 was added due to it is an inorganic drying agent that binds strongly with water and thus removes any traces of water from the solution. Besides that, our group put wrong magnesium sulphate heptahydate to remove the water, this affect the yield that we got. Precaution steps: Phosphoric acids are strong, corrosive acids. If any acid is splashed on your skin or clothing, wash immediately with copious amounts of water. Cyclohexene and toluene are not particularly dangerous but are highly flammable. Both are quite painful if splashed in the eyes and must be removed by extensive eye washing. Remaining cyclohexene should be disposed of in the fume-hood sink because cyclohexene vapors are heavier than air, they will accumulate in the sink. Conclusion: 2.55 g of cyclohexene was produced, which is 31.41% from the theoretical mass. The loss of water from a cyclohexanol to give a cyclohexene does not occur in just one step; a series of steps are involved in the mechanism of dehydration of alcohols. References: Reference books: T.W.G. Solomons and C. Fryhle, Organic Chemistry, Chapter 7.7, Dehydration of Alcohols. K. L. Williamson, Macroscale and Microscale Organic Experiments, 2nd Ed. 1994, Houghton Mifflin, Boston d. p268 McMurry, J. (2008). Organic Chemistry 7th ed. Brooks/Cole: Thomson Learning. P619-621 Webpages: Preparation of Cyclohexene from Cyclohexanol: an Elimination Reaction. http://www4.napavalley.edu/Projects/1334/Chem_240_-_Labs/Expt_05_-_Synthesis_of_Cyclohexene_from_Cyclohexanol.pdf Synthesis of Cyclohexene The Dehydration of Cyclohexanol. http://www.chem.umass.edu/~samal/269/cyclohexene.pdf Synthesis of Cyclohexene from Cyclohexanol by ( E1 ) Elimination. http://academic.keystone.edu/JFalcone/SynthesisCyclohexene.htm